5^(x^2+40x)=5^(-144)

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Solution for 5^(x^2+40x)=5^(-144) equation:



5^(x^2+40x)=5^(-144)
We move all terms to the left:
5^(x^2+40x)-(5^(-144))=0
We add all the numbers together, and all the variables
5^(x^2+40x)-101-2.2300745198531E=0
We add all the numbers together, and all the variables
5^(x^2+40x)-107.06197104343=0
We move all terms containing x to the left, all other terms to the right
5^(x^2+40x)=107.06197104343

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